Base | Representation |
---|---|
bin | 11001000000110110111001… |
… | …100001110011101110010111 |
3 | 112102111212022201021222220101 |
4 | 121000312321201303232113 |
5 | 103404401201130000043 |
6 | 1025545540304114531 |
7 | 32112653036223352 |
oct | 3100667141635627 |
9 | 472455281258811 |
10 | 110010110000023 |
11 | 32064031156912 |
12 | 10408843305a47 |
13 | 494cba79c3cac |
14 | 1d24736939299 |
15 | cab93709d24d |
hex | 640db9873b97 |
110010110000023 has 2 divisors, whose sum is σ = 110010110000024. Its totient is φ = 110010110000022.
The previous prime is 110010109999997. The next prime is 110010110000027. The reversal of 110010110000023 is 320000011010011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110010110000023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 110010109999964 and 110010110000009.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110010110000027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005055000011 + 55005055000012.
It is an arithmetic number, because the mean of its divisors is an integer number (55005055000012).
Almost surely, 2110010110000023 is an apocalyptic number.
110010110000023 is a deficient number, since it is larger than the sum of its proper divisors (1).
110010110000023 is an equidigital number, since it uses as much as digits as its factorization.
110010110000023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6, while the sum is 10.
Adding to 110010110000023 its reverse (320000011010011), we get a palindrome (430010121010034).
The spelling of 110010110000023 in words is "one hundred ten trillion, ten billion, one hundred ten million, twenty-three", and thus it is an aban number.
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