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11001021012133 is a prime number
BaseRepresentation
bin1010000000010101111111…
…1100110001100010100101
31102221200120001212110122121
42200011133330301202211
52420220042334342013
635221444351225541
72213540361510145
oct240053774614245
942850501773577
1011001021012133
113561563624499
1212980a38182b1
1361a512b0a249
142a0648dd2925
1514126613b58d
hexa015ff318a5

11001021012133 has 2 divisors, whose sum is σ = 11001021012134. Its totient is φ = 11001021012132.

The previous prime is 11001021012097. The next prime is 11001021012203. The reversal of 11001021012133 is 33121012010011.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10925655938404 + 75365073729 = 3305398^2 + 274527^2 .

It is an emirp because it is prime and its reverse (33121012010011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11001021012133 - 213 = 11001021003941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11001021012833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500510506066 + 5500510506067.

It is an arithmetic number, because the mean of its divisors is an integer number (5500510506067).

Almost surely, 211001021012133 is an apocalyptic number.

It is an amenable number.

11001021012133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001021012133 is an equidigital number, since it uses as much as digits as its factorization.

11001021012133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 11001021012133 its reverse (33121012010011), we get a palindrome (44122033022144).

The spelling of 11001021012133 in words is "eleven trillion, one billion, twenty-one million, twelve thousand, one hundred thirty-three".