Base | Representation |
---|---|
bin | 1010000000010110001000… |
… | …0010000000110111010101 |
3 | 1102221200122111120222202021 |
4 | 2200011202002000313111 |
5 | 2420220130310040203 |
6 | 35221452040013141 |
7 | 2213541264421624 |
oct | 240054202006725 |
9 | 42850574528667 |
10 | 11001055940053 |
11 | 3561581310343 |
12 | 12980b34611b1 |
13 | 61a51a11925a |
14 | 2a064d8c56bb |
15 | 14126923a5bd |
hex | a0162080dd5 |
11001055940053 has 2 divisors, whose sum is σ = 11001055940054. Its totient is φ = 11001055940052.
The previous prime is 11001055939969. The next prime is 11001055940071. The reversal of 11001055940053 is 35004955010011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9916912686769 + 1084143253284 = 3149113^2 + 1041222^2 .
It is a cyclic number.
It is not a de Polignac number, because 11001055940053 - 213 = 11001055931861 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11001055940093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500527970026 + 5500527970027.
It is an arithmetic number, because the mean of its divisors is an integer number (5500527970027).
Almost surely, 211001055940053 is an apocalyptic number.
It is an amenable number.
11001055940053 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001055940053 is an equidigital number, since it uses as much as digits as its factorization.
11001055940053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13500, while the sum is 34.
The spelling of 11001055940053 in words is "eleven trillion, one billion, fifty-five million, nine hundred forty thousand, fifty-three".
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