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11001055940053 is a prime number
BaseRepresentation
bin1010000000010110001000…
…0010000000110111010101
31102221200122111120222202021
42200011202002000313111
52420220130310040203
635221452040013141
72213541264421624
oct240054202006725
942850574528667
1011001055940053
113561581310343
1212980b34611b1
1361a51a11925a
142a064d8c56bb
1514126923a5bd
hexa0162080dd5

11001055940053 has 2 divisors, whose sum is σ = 11001055940054. Its totient is φ = 11001055940052.

The previous prime is 11001055939969. The next prime is 11001055940071. The reversal of 11001055940053 is 35004955010011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9916912686769 + 1084143253284 = 3149113^2 + 1041222^2 .

It is a cyclic number.

It is not a de Polignac number, because 11001055940053 - 213 = 11001055931861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11001055940093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500527970026 + 5500527970027.

It is an arithmetic number, because the mean of its divisors is an integer number (5500527970027).

Almost surely, 211001055940053 is an apocalyptic number.

It is an amenable number.

11001055940053 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001055940053 is an equidigital number, since it uses as much as digits as its factorization.

11001055940053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13500, while the sum is 34.

The spelling of 11001055940053 in words is "eleven trillion, one billion, fifty-five million, nine hundred forty thousand, fifty-three".