Base | Representation |
---|---|
bin | 1010000000010110001000… |
… | …0010010000110101110101 |
3 | 1102221200122111201022111222 |
4 | 2200011202002100311311 |
5 | 2420220130314133433 |
6 | 35221452041240125 |
7 | 2213541265113461 |
oct | 240054202206565 |
9 | 42850574638458 |
10 | 11001056005493 |
11 | 3561581355524 |
12 | 12980b3493045 |
13 | 61a51a13cc88 |
14 | 2a064d9014a1 |
15 | 14126924eb98 |
hex | a0162090d75 |
11001056005493 has 2 divisors, whose sum is σ = 11001056005494. Its totient is φ = 11001056005492.
The previous prime is 11001056005447. The next prime is 11001056005507. The reversal of 11001056005493 is 39450065010011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10586290380964 + 414765624529 = 3253658^2 + 644023^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11001056005493 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11001056095493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500528002746 + 5500528002747.
It is an arithmetic number, because the mean of its divisors is an integer number (5500528002747).
Almost surely, 211001056005493 is an apocalyptic number.
It is an amenable number.
11001056005493 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001056005493 is an equidigital number, since it uses as much as digits as its factorization.
11001056005493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16200, while the sum is 35.
The spelling of 11001056005493 in words is "eleven trillion, one billion, fifty-six million, five thousand, four hundred ninety-three".
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