Base | Representation |
---|---|
bin | 1010000000010110001000… |
… | …0010100110110100000101 |
3 | 1102221200122111212212222022 |
4 | 2200011202002212310011 |
5 | 2420220130330023433 |
6 | 35221452043212525 |
7 | 2213541265640042 |
oct | 240054202466405 |
9 | 42850574785868 |
10 | 11001056095493 |
11 | 3561581407102 |
12 | 12980b3517145 |
13 | 61a51a171c29 |
14 | 2a064d9261c9 |
15 | 14126926b698 |
hex | a01620a6d05 |
11001056095493 has 2 divisors, whose sum is σ = 11001056095494. Its totient is φ = 11001056095492.
The previous prime is 11001056095441. The next prime is 11001056095511. The reversal of 11001056095493 is 39459065010011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8507821411489 + 2493234684004 = 2916817^2 + 1578998^2 .
It is a cyclic number.
It is not a de Polignac number, because 11001056095493 - 226 = 11000988986629 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11001056005493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500528047746 + 5500528047747.
It is an arithmetic number, because the mean of its divisors is an integer number (5500528047747).
Almost surely, 211001056095493 is an apocalyptic number.
It is an amenable number.
11001056095493 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001056095493 is an equidigital number, since it uses as much as digits as its factorization.
11001056095493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 145800, while the sum is 44.
The spelling of 11001056095493 in words is "eleven trillion, one billion, fifty-six million, ninety-five thousand, four hundred ninety-three".
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