Base | Representation |
---|---|
bin | 11001000000110111101110… |
… | …100100111000111010001101 |
3 | 112102111221121201222200112201 |
4 | 121000313232210320322031 |
5 | 103404410012000001031 |
6 | 1025550204500001501 |
7 | 32113014064133032 |
oct | 3100675644707215 |
9 | 472457551880481 |
10 | 110011000000141 |
11 | 320644485790a9 |
12 | 10408a51390291 |
13 | 494ccba1c8b96 |
14 | 1d247bcc11389 |
15 | cab98a2a1d61 |
hex | 640dee938e8d |
110011000000141 has 2 divisors, whose sum is σ = 110011000000142. Its totient is φ = 110011000000140.
The previous prime is 110011000000129. The next prime is 110011000000243. The reversal of 110011000000141 is 141000000110011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 88048383228100 + 21962616772041 = 9383410^2 + 4686429^2 .
It is a cyclic number.
It is not a de Polignac number, because 110011000000141 - 211 = 110010999998093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110011000007141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005500000070 + 55005500000071.
It is an arithmetic number, because the mean of its divisors is an integer number (55005500000071).
Almost surely, 2110011000000141 is an apocalyptic number.
It is an amenable number.
110011000000141 is a deficient number, since it is larger than the sum of its proper divisors (1).
110011000000141 is an equidigital number, since it uses as much as digits as its factorization.
110011000000141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 10.
Adding to 110011000000141 its reverse (141000000110011), we get a palindrome (251011000110152).
The spelling of 110011000000141 in words is "one hundred ten trillion, eleven billion, one hundred forty-one", and thus it is an aban number.
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