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110011000000141 is a prime number
BaseRepresentation
bin11001000000110111101110…
…100100111000111010001101
3112102111221121201222200112201
4121000313232210320322031
5103404410012000001031
61025550204500001501
732113014064133032
oct3100675644707215
9472457551880481
10110011000000141
11320644485790a9
1210408a51390291
13494ccba1c8b96
141d247bcc11389
15cab98a2a1d61
hex640dee938e8d

110011000000141 has 2 divisors, whose sum is σ = 110011000000142. Its totient is φ = 110011000000140.

The previous prime is 110011000000129. The next prime is 110011000000243. The reversal of 110011000000141 is 141000000110011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 88048383228100 + 21962616772041 = 9383410^2 + 4686429^2 .

It is a cyclic number.

It is not a de Polignac number, because 110011000000141 - 211 = 110010999998093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110011000007141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005500000070 + 55005500000071.

It is an arithmetic number, because the mean of its divisors is an integer number (55005500000071).

Almost surely, 2110011000000141 is an apocalyptic number.

It is an amenable number.

110011000000141 is a deficient number, since it is larger than the sum of its proper divisors (1).

110011000000141 is an equidigital number, since it uses as much as digits as its factorization.

110011000000141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 10.

Adding to 110011000000141 its reverse (141000000110011), we get a palindrome (251011000110152).

The spelling of 110011000000141 in words is "one hundred ten trillion, eleven billion, one hundred forty-one", and thus it is an aban number.