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1100110100053 is a prime number
BaseRepresentation
bin10000000000100011101…
…010111111011001010101
310220011120120020102121111
4100000203222333121111
5121011011141200203
62201214505215021
7142323516363646
oct20004352773125
93804516212544
101100110100053
11394610520878
12159260791471
137c980847033
143b361d676cd
151d93a49d26d
hex10023abf655

1100110100053 has 2 divisors, whose sum is σ = 1100110100054. Its totient is φ = 1100110100052.

The previous prime is 1100110100051. The next prime is 1100110100119. The reversal of 1100110100053 is 3500010110011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1080481249444 + 19628850609 = 1039462^2 + 140103^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100110100053 - 21 = 1100110100051 is a prime.

Together with 1100110100051, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100110100051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550055050026 + 550055050027.

It is an arithmetic number, because the mean of its divisors is an integer number (550055050027).

Almost surely, 21100110100053 is an apocalyptic number.

It is an amenable number.

1100110100053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100110100053 is an equidigital number, since it uses as much as digits as its factorization.

1100110100053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15, while the sum is 13.

Adding to 1100110100053 its reverse (3500010110011), we get a palindrome (4600120210064).

The spelling of 1100110100053 in words is "one trillion, one hundred billion, one hundred ten million, one hundred thousand, fifty-three".