11001101000993 has 2 divisors, whose sum is σ = 11001101000994. Its totient is φ = 11001101000992.

The previous prime is 11001101000983. The next prime is 11001101000999. The reversal of 11001101000993 is 39900010110011.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10008162490624 + 992938510369 = 3163568^2 + 996463^2 .

It is an emirp because it is prime and its reverse (39900010110011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11001101000993 - 2⁸ = 11001101000737 is a prime.

It is not a weakly prime, because it can be changed into another prime (11001101000999) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500550500496 + 5500550500497.

It is an arithmetic number, because the mean of its divisors is an integer number (5500550500497).

Almost surely, 2^{11001101000993} is an apocalyptic number.

It is an amenable number.

11001101000993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001101000993 is an equidigital number, since it uses as much as digits as its factorization.

11001101000993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 26.

The spelling of 11001101000993 in words is "eleven trillion, one billion, one hundred one million, nine hundred ninety-three", and thus it is an aban number.