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11001101220047 is a prime number
BaseRepresentation
bin1010000000010110010010…
…1110101111100011001111
31102221200202122210110020002
42200011210232233203033
52420220223403020142
635221500334314515
72213542354330361
oct240054456574317
942850678713202
1011001101220047
1135615a4927924
121298106658a3b
1361a526611153
142a0655910d31
1514126d1d1a32
hexa0164baf8cf

11001101220047 has 2 divisors, whose sum is σ = 11001101220048. Its totient is φ = 11001101220046.

The previous prime is 11001101220029. The next prime is 11001101220071. The reversal of 11001101220047 is 74002210110011.

11001101220047 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11001101220047 - 28 = 11001101219791 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11001101220947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500550610023 + 5500550610024.

It is an arithmetic number, because the mean of its divisors is an integer number (5500550610024).

Almost surely, 211001101220047 is an apocalyptic number.

11001101220047 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001101220047 is an equidigital number, since it uses as much as digits as its factorization.

11001101220047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 112, while the sum is 20.

Adding to 11001101220047 its reverse (74002210110011), we get a palindrome (85003311330058).

The spelling of 11001101220047 in words is "eleven trillion, one billion, one hundred one million, two hundred twenty thousand, forty-seven".