Base | Representation |
---|---|
bin | 11001000000110111110100… |
… | …100010010001110010100111 |
3 | 112102111221212201010010122102 |
4 | 121000313310202101302213 |
5 | 103404410213043311134 |
6 | 1025550222430522315 |
7 | 32113016420006246 |
oct | 3100676442216247 |
9 | 472457781103572 |
10 | 110011099978919 |
11 | 32064499a55697 |
12 | 10408a7a96639b |
13 | 4950004b32b19 |
14 | 1d247cc1d895d |
15 | cab993e5037e |
hex | 640df4891ca7 |
110011099978919 has 2 divisors, whose sum is σ = 110011099978920. Its totient is φ = 110011099978918.
The previous prime is 110011099978907. The next prime is 110011099978921. The reversal of 110011099978919 is 919879990110011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110011099978919 is a prime.
It is a super-2 number, since 2×1100110999789192 (a number of 29 digits) contains 22 as substring.
Together with 110011099978921, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110011099971919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005549989459 + 55005549989460.
It is an arithmetic number, because the mean of its divisors is an integer number (55005549989460).
Almost surely, 2110011099978919 is an apocalyptic number.
110011099978919 is a deficient number, since it is larger than the sum of its proper divisors (1).
110011099978919 is an equidigital number, since it uses as much as digits as its factorization.
110011099978919 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3306744, while the sum is 65.
The spelling of 110011099978919 in words is "one hundred ten trillion, eleven billion, ninety-nine million, nine hundred seventy-eight thousand, nine hundred nineteen".
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