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1100111107453 is a prime number
BaseRepresentation
bin10000000000100011101…
…110110101010101111101
310220011120122010121111121
4100000203232311111331
5121011011420414303
62201214542550541
7142323531060661
oct20004356652575
93804518117447
101100111107453
11394611049736
12159260b98451
137c980b0a727
143b36214a8a1
151d93a5eb9bd
hex10023bb557d

1100111107453 has 2 divisors, whose sum is σ = 1100111107454. Its totient is φ = 1100111107452.

The previous prime is 1100111107439. The next prime is 1100111107493. The reversal of 1100111107453 is 3547011110011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1079225944164 + 20885163289 = 1038858^2 + 144517^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100111107453 - 213 = 1100111099261 is a prime.

It is a super-2 number, since 2×11001111074532 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100111107493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550055553726 + 550055553727.

It is an arithmetic number, because the mean of its divisors is an integer number (550055553727).

Almost surely, 21100111107453 is an apocalyptic number.

It is an amenable number.

1100111107453 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100111107453 is an equidigital number, since it uses as much as digits as its factorization.

1100111107453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 420, while the sum is 25.

Adding to 1100111107453 its reverse (3547011110011), we get a palindrome (4647122217464).

The spelling of 1100111107453 in words is "one trillion, one hundred billion, one hundred eleven million, one hundred seven thousand, four hundred fifty-three".