Base | Representation |
---|---|
bin | 1010000000010110010101… |
… | …0100111000111101110111 |
3 | 1102221200210100121111200221 |
4 | 2200011211110320331313 |
5 | 2420220233433020322 |
6 | 35221501332515211 |
7 | 2213542535330122 |
oct | 240054524707567 |
9 | 42850710544627 |
10 | 11001111220087 |
11 | 35615aa53801a |
12 | 1298109a7bb07 |
13 | 61a528702a31 |
14 | 2a0656d953b9 |
15 | 14126e0099c7 |
hex | a0165538f77 |
11001111220087 has 2 divisors, whose sum is σ = 11001111220088. Its totient is φ = 11001111220086.
The previous prime is 11001111220081. The next prime is 11001111220139. The reversal of 11001111220087 is 78002211110011.
11001111220087 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (78002211110011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11001111220087 - 223 = 11001102831479 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11001111220081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500555610043 + 5500555610044.
It is an arithmetic number, because the mean of its divisors is an integer number (5500555610044).
Almost surely, 211001111220087 is an apocalyptic number.
11001111220087 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001111220087 is an equidigital number, since it uses as much as digits as its factorization.
11001111220087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 25.
Adding to 11001111220087 its reverse (78002211110011), we get a palindrome (89003322330098).
The spelling of 11001111220087 in words is "eleven trillion, one billion, one hundred eleven million, two hundred twenty thousand, eighty-seven".
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