Base | Representation |
---|---|
bin | 10000000000100011101… |
… | …111010001000110000111 |
3 | 10220011120122100101102202 |
4 | 100000203233101012013 |
5 | 121011011433034002 |
6 | 2201214545225115 |
7 | 142323532043252 |
oct | 20004357210607 |
9 | 3804518311382 |
10 | 1100111221127 |
11 | 394611117086 |
12 | 15926103219b |
13 | 7c980b4a3a9 |
14 | 3b36217a099 |
15 | 1d93a620502 |
hex | 10023bd1187 |
1100111221127 has 2 divisors, whose sum is σ = 1100111221128. Its totient is φ = 1100111221126.
The previous prime is 1100111221061. The next prime is 1100111221177. The reversal of 1100111221127 is 7211221110011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1100111221127 - 214 = 1100111204743 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1100111221099 and 1100111221108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100111221177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550055610563 + 550055610564.
It is an arithmetic number, because the mean of its divisors is an integer number (550055610564).
Almost surely, 21100111221127 is an apocalyptic number.
1100111221127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100111221127 is an equidigital number, since it uses as much as digits as its factorization.
1100111221127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 1100111221127 its reverse (7211221110011), we get a palindrome (8311332331138).
The spelling of 1100111221127 in words is "one trillion, one hundred billion, one hundred eleven million, two hundred twenty-one thousand, one hundred twenty-seven".
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