Base | Representation |
---|---|
bin | 10000000000100011101… |
… | …111101100011011111111 |
3 | 10220011120122120002001121 |
4 | 100000203233230123333 |
5 | 121011012000124434 |
6 | 2201214551451411 |
7 | 142323533020621 |
oct | 20004357543377 |
9 | 3804518502047 |
10 | 1100111333119 |
11 | 394611193237 |
12 | 159261086b67 |
13 | 7c980b89366 |
14 | 3b3621a8c11 |
15 | 1d93a6437b4 |
hex | 10023bec6ff |
1100111333119 has 2 divisors, whose sum is σ = 1100111333120. Its totient is φ = 1100111333118.
The previous prime is 1100111333093. The next prime is 1100111333161. The reversal of 1100111333119 is 9113331110011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1100111333119 - 225 = 1100077778687 is a prime.
It is a super-2 number, since 2×11001113331192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1100111333093 and 1100111333102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100111333219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550055666559 + 550055666560.
It is an arithmetic number, because the mean of its divisors is an integer number (550055666560).
Almost surely, 21100111333119 is an apocalyptic number.
1100111333119 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100111333119 is an equidigital number, since it uses as much as digits as its factorization.
1100111333119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 25.
The spelling of 1100111333119 in words is "one trillion, one hundred billion, one hundred eleven million, three hundred thirty-three thousand, one hundred nineteen".
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