Base | Representation |
---|---|
bin | 10000000000100011110… |
… | …010010100101011001111 |
3 | 10220011120200212002022222 |
4 | 100000203302110223033 |
5 | 121011012134202343 |
6 | 2201215014325555 |
7 | 142323541620644 |
oct | 20004362245317 |
9 | 3804520762288 |
10 | 1100112022223 |
11 | 394611613a45 |
12 | 1592613598bb |
13 | 7c98106ac06 |
14 | 3b362307dcb |
15 | 1d93a72ca68 |
hex | 10023c94acf |
1100112022223 has 2 divisors, whose sum is σ = 1100112022224. Its totient is φ = 1100112022222.
The previous prime is 1100112022211. The next prime is 1100112022241. The reversal of 1100112022223 is 3222202110011.
It is a weak prime.
It is an emirp because it is prime and its reverse (3222202110011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1100112022223 - 26 = 1100112022159 is a prime.
It is a super-2 number, since 2×11001120222232 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100112022253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550056011111 + 550056011112.
It is an arithmetic number, because the mean of its divisors is an integer number (550056011112).
Almost surely, 21100112022223 is an apocalyptic number.
1100112022223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100112022223 is an equidigital number, since it uses as much as digits as its factorization.
1100112022223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 1100112022223 its reverse (3222202110011), we get a palindrome (4322314132234).
The spelling of 1100112022223 in words is "one trillion, one hundred billion, one hundred twelve million, twenty-two thousand, two hundred twenty-three".
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