Base | Representation |
---|---|
bin | 11001000000110111111011… |
… | …110000010111000100000111 |
3 | 112102111222012011001021200112 |
4 | 121000313323300113010013 |
5 | 103404410440101023142 |
6 | 1025550242435103235 |
7 | 32113022420424164 |
oct | 3100677360270407 |
9 | 472458164037615 |
10 | 110011221111047 |
11 | 3206455136aa93 |
12 | 10408ab3441b1b |
13 | 4950023c65139 |
14 | 1d2480032b06b |
15 | cab99e8cb382 |
hex | 640dfbc17107 |
110011221111047 has 2 divisors, whose sum is σ = 110011221111048. Its totient is φ = 110011221111046.
The previous prime is 110011221110993. The next prime is 110011221111053. The reversal of 110011221111047 is 740111122110011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110011221111047 - 242 = 105613174599943 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110011223111047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005610555523 + 55005610555524.
It is an arithmetic number, because the mean of its divisors is an integer number (55005610555524).
Almost surely, 2110011221111047 is an apocalyptic number.
110011221111047 is a deficient number, since it is larger than the sum of its proper divisors (1).
110011221111047 is an equidigital number, since it uses as much as digits as its factorization.
110011221111047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 23.
Adding to 110011221111047 its reverse (740111122110011), we get a palindrome (850122343221058).
The spelling of 110011221111047 in words is "one hundred ten trillion, eleven billion, two hundred twenty-one million, one hundred eleven thousand, forty-seven".
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