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110012011200000 = 293255713372269
BaseRepresentation
bin11001000000111000101010…
…110110010011111000000000
3112102112001020012201221222100
4121000320222312103320000
5103404414044331400000
61025550453101310400
732113051123161420
oct3100705266237000
9472461205657870
10110012011200000
1132064917351568
1210409093b65400
13495011b857ab0
141d24877236480
15cab9e8e46a00
hex640e2ad93e00

110012011200000 has 2880 divisors, whose sum is σ = 501855515441280. Its totient is φ = 22574039040000.

The previous prime is 110012011199887. The next prime is 110012011200011. The reversal of 110012011200000 is 2110210011.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (2880).

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a super Niven number, because it is divisible the sum of any subset of its (nonzero) digits.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 48484798866 + ... + 48484801134.

It is an arithmetic number, because the mean of its divisors is an integer number (174255387306).

Almost surely, 2110012011200000 is an apocalyptic number.

110012011200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 110012011200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (250927757720640).

110012011200000 is an abundant number, since it is smaller than the sum of its proper divisors (391843504241280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110012011200000 is an equidigital number, since it uses as much as digits as its factorization.

110012011200000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2375 (or 2336 counting only the distinct ones).

The product of its (nonzero) digits is 4, while the sum is 9.

Adding to 110012011200000 its reverse (2110210011), we get a palindrome (110014121410011).

It can be divided in two parts, 110012011 and 200000, that added together give a palindrome (110212011).

The spelling of 110012011200000 in words is "one hundred ten trillion, twelve billion, eleven million, two hundred thousand".