110012109973 has 2 divisors, whose sum is σ = 110012109974. Its totient is φ = 110012109972.

The previous prime is 110012109967. The next prime is 110012110001. The reversal of 110012109973 is 379901210011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 83035032964 + 26977077009 = 288158^2 + 164247^2 .

It is a cyclic number.

It is not a de Polignac number, because 110012109973 - 2⁵ = 110012109941 is a prime.

It is a super-2 number, since 2×110012109973² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110012109943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006054986 + 55006054987.

It is an arithmetic number, because the mean of its divisors is an integer number (55006054987).

Almost surely, 2^110012109973 is an apocalyptic number.

It is an amenable number.

110012109973 is a deficient number, since it is larger than the sum of its proper divisors (1).

110012109973 is an equidigital number, since it uses as much as digits as its factorization.

110012109973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3402, while the sum is 34.

Adding to 110012109973 its reverse (379901210011), we get a palindrome (489913319984).

The spelling of 110012109973 in words is "one hundred ten billion, twelve million, one hundred nine thousand, nine hundred seventy-three".