Base | Representation |
---|---|
bin | 1010000000010110101101… |
… | …0010010101000101001011 |
3 | 1102221201001022202121222002 |
4 | 2200011223102111011023 |
5 | 2420220440032241412 |
6 | 35221515304021215 |
7 | 2213545161260054 |
oct | 240055322250513 |
9 | 42851038677862 |
10 | 11001211212107 |
11 | 3561650a23556 |
12 | 129813746180b |
13 | 61a5433429cc |
14 | 2a066638372b |
15 | 141277babdc2 |
hex | a016b49514b |
11001211212107 has 2 divisors, whose sum is σ = 11001211212108. Its totient is φ = 11001211212106.
The previous prime is 11001211212097. The next prime is 11001211212109. The reversal of 11001211212107 is 70121211210011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11001211212107 - 228 = 11000942776651 is a prime.
Together with 11001211212109, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11001211212109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500605606053 + 5500605606054.
It is an arithmetic number, because the mean of its divisors is an integer number (5500605606054).
Almost surely, 211001211212107 is an apocalyptic number.
11001211212107 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001211212107 is an equidigital number, since it uses as much as digits as its factorization.
11001211212107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 11001211212107 its reverse (70121211210011), we get a palindrome (81122422422118).
The spelling of 11001211212107 in words is "eleven trillion, one billion, two hundred eleven million, two hundred twelve thousand, one hundred seven".
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