Base | Representation |
---|---|
bin | 10100011111011100… |
… | …10010110010110011 |
3 | 1001101200201110220101 |
4 | 22033232102302303 |
5 | 140012302241313 |
6 | 5015350053231 |
7 | 536422521421 |
oct | 121756226263 |
9 | 31350643811 |
10 | 11001212083 |
11 | 4735996514 |
12 | 217034a217 |
13 | 1064260264 |
14 | 765108111 |
15 | 445c2d5dd |
hex | 28fb92cb3 |
11001212083 has 2 divisors, whose sum is σ = 11001212084. Its totient is φ = 11001212082.
The previous prime is 11001212081. The next prime is 11001212113. The reversal of 11001212083 is 38021210011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11001212083 - 21 = 11001212081 is a prime.
Together with 11001212081, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 11001212083.
It is not a weakly prime, because it can be changed into another prime (11001212081) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500606041 + 5500606042.
It is an arithmetic number, because the mean of its divisors is an integer number (5500606042).
Almost surely, 211001212083 is an apocalyptic number.
11001212083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001212083 is an equidigital number, since it uses as much as digits as its factorization.
11001212083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 11001212083 its reverse (38021210011), we get a palindrome (49022422094).
The spelling of 11001212083 in words is "eleven billion, one million, two hundred twelve thousand, eighty-three".
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