Base | Representation |
---|---|
bin | 110011001110100111… |
… | …1010010011111110111 |
3 | 101111221221101110210021 |
4 | 1212131033102133313 |
5 | 3300301111310424 |
6 | 122312223310011 |
7 | 10643130245365 |
oct | 1463517223767 |
9 | 344857343707 |
10 | 110012213239 |
11 | 427240320a5 |
12 | 193a2a4b307 |
13 | a4b2bb4c86 |
14 | 5478a82635 |
15 | 2cdd20b4e4 |
hex | 199d3d27f7 |
110012213239 has 2 divisors, whose sum is σ = 110012213240. Its totient is φ = 110012213238.
The previous prime is 110012213221. The next prime is 110012213293. The reversal of 110012213239 is 932312210011.
Together with next prime (110012213293) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110012213239 - 27 = 110012213111 is a prime.
It is a super-2 number, since 2×1100122132392 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110012283239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006106619 + 55006106620.
It is an arithmetic number, because the mean of its divisors is an integer number (55006106620).
Almost surely, 2110012213239 is an apocalyptic number.
110012213239 is a deficient number, since it is larger than the sum of its proper divisors (1).
110012213239 is an equidigital number, since it uses as much as digits as its factorization.
110012213239 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 110012213239 in words is "one hundred ten billion, twelve million, two hundred thirteen thousand, two hundred thirty-nine".
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