110013020197 has 2 divisors, whose sum is σ = 110013020198. Its totient is φ = 110013020196.

The previous prime is 110013020099. The next prime is 110013020207. The reversal of 110013020197 is 791020310011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 103294103236 + 6718916961 = 321394^2 + 81969^2 .

It is an emirp because it is prime and its reverse (791020310011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110013020197 - 2¹¹ = 110013018149 is a prime.

It is a super-2 number, since 2×110013020197² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110013020497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006510098 + 55006510099.

It is an arithmetic number, because the mean of its divisors is an integer number (55006510099).

Almost surely, 2^110013020197 is an apocalyptic number.

It is an amenable number.

110013020197 is a deficient number, since it is larger than the sum of its proper divisors (1).

110013020197 is an equidigital number, since it uses as much as digits as its factorization.

110013020197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 378, while the sum is 25.

The spelling of 110013020197 in words is "one hundred ten billion, thirteen million, twenty thousand, one hundred ninety-seven".