11001313303 has 2 divisors, whose sum is σ = 11001313304. Its totient is φ = 11001313302.

The previous prime is 11001313289. The next prime is 11001313319. The reversal of 11001313303 is 30331310011.

It is an a-pointer prime, because the next prime (11001313319) can be obtained adding 11001313303 to its sum of digits (16).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11001313303 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11001313373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500656651 + 5500656652.

It is an arithmetic number, because the mean of its divisors is an integer number (5500656652).

Almost surely, 2^11001313303 is an apocalyptic number.

11001313303 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001313303 is an equidigital number, since it uses as much as digits as its factorization.

11001313303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 11001313303 its reverse (30331310011), we get a palindrome (41332623314).

The spelling of 11001313303 in words is "eleven billion, one million, three hundred thirteen thousand, three hundred three".