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11001330311120 = 245157978705237
BaseRepresentation
bin1010000000010111001001…
…1000101001111111010000
31102221201100121212111002122
42200011302120221333100
52420221211024423440
635221535200433412
72213551135506362
oct240056230517720
942851317774078
1011001330311120
11356170217a396
12129816b318868
1361a561c127b6
142a0678106d32
151412833857b5
hexa0172629fd0

11001330311120 has 40 divisors (see below), whose sum is σ = 25579715085864. Its totient is φ = 4400253051392.

The previous prime is 11001330311003. The next prime is 11001330311123. The reversal of 11001330311120 is 2111303310011.

It can be written as a sum of positive squares in 4 ways, for example, as 1521877518736 + 9479452792384 = 1233644^2 + 3078872^2 .

It is a tau number, because it is divible by the number of its divisors (40).

It is a super-2 number, since 2×110013303111202 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11001330311123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3088859 + ... + 5616378.

Almost surely, 211001330311120 is an apocalyptic number.

11001330311120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11001330311120 is an abundant number, since it is smaller than the sum of its proper divisors (14578384774744).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11001330311120 is a wasteful number, since it uses less digits than its factorization.

11001330311120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8721047 (or 8721041 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11001330311120 its reverse (2111303310011), we get a palindrome (13112633621131).

The spelling of 11001330311120 in words is "eleven trillion, one billion, three hundred thirty million, three hundred eleven thousand, one hundred twenty".

Divisors: 1 2 4 5 8 10 16 20 40 80 15797 31594 63188 78985 126376 157970 252752 315940 631880 1263760 8705237 17410474 34820948 43526185 69641896 87052370 139283792 174104740 348209480 696418960 137516628889 275033257778 550066515556 687583144445 1100133031112 1375166288890 2200266062224 2750332577780 5500665155560 11001330311120