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1100201400457 is a prime number
BaseRepresentation
bin10000000000101001000…
…111010001100010001001
310220011210221000222012221
4100000221013101202021
5121011203024303312
62201231530134041
7142326005413615
oct20005107214211
93804727028187
101100201400457
11394658010155
12159287281321
137c996732b43
143b370132345
151d9434d5207
hex100291d1889

1100201400457 has 2 divisors, whose sum is σ = 1100201400458. Its totient is φ = 1100201400456.

The previous prime is 1100201400407. The next prime is 1100201400469. The reversal of 1100201400457 is 7540041020011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 793843578441 + 306357822016 = 890979^2 + 553496^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100201400457 - 27 = 1100201400329 is a prime.

It is not a weakly prime, because it can be changed into another prime (1100201400407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550100700228 + 550100700229.

It is an arithmetic number, because the mean of its divisors is an integer number (550100700229).

Almost surely, 21100201400457 is an apocalyptic number.

It is an amenable number.

1100201400457 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100201400457 is an equidigital number, since it uses as much as digits as its factorization.

1100201400457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1120, while the sum is 25.

Adding to 1100201400457 its reverse (7540041020011), we get a palindrome (8640242420468).

The spelling of 1100201400457 in words is "one trillion, one hundred billion, two hundred one million, four hundred thousand, four hundred fifty-seven".