Base | Representation |
---|---|
bin | 10000000000101001001… |
… | …001100011111010101111 |
3 | 10220011210222011102200222 |
4 | 100000221021203322233 |
5 | 121011203203000142 |
6 | 2201231551041555 |
7 | 142326013461653 |
oct | 20005111437257 |
9 | 3804728142628 |
10 | 1100202000047 |
11 | 39465838a687 |
12 | 1592875102bb |
13 | 7c9968b2a27 |
14 | 3b37024aa63 |
15 | 1d9435a2bd2 |
hex | 10029263eaf |
1100202000047 has 2 divisors, whose sum is σ = 1100202000048. Its totient is φ = 1100202000046.
The previous prime is 1100202000031. The next prime is 1100202000119. The reversal of 1100202000047 is 7400002020011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1100202000047 - 24 = 1100202000031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1100201999989 and 1100202000034.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100202000017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550101000023 + 550101000024.
It is an arithmetic number, because the mean of its divisors is an integer number (550101000024).
Almost surely, 21100202000047 is an apocalyptic number.
1100202000047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100202000047 is an equidigital number, since it uses as much as digits as its factorization.
1100202000047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 17.
Adding to 1100202000047 its reverse (7400002020011), we get a palindrome (8500204020058).
The spelling of 1100202000047 in words is "one trillion, one hundred billion, two hundred two million, forty-seven", and thus it is an aban number.
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