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1100202012181 is a prime number
BaseRepresentation
bin10000000000101001001…
…001100110111000010101
310220011210222012001100101
4100000221021212320111
5121011203203342211
62201231551214101
7142326013542226
oct20005111467025
93804728161311
101100202012181
11394658398808
12159287517331
137c9968b83cc
143b37025124d
151d9435a65c1
hex10029266e15

1100202012181 has 2 divisors, whose sum is σ = 1100202012182. Its totient is φ = 1100202012180.

The previous prime is 1100202012127. The next prime is 1100202012223. The reversal of 1100202012181 is 1812102020011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 641072448900 + 459129563281 = 800670^2 + 677591^2 .

It is an emirp because it is prime and its reverse (1812102020011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100202012181 - 27 = 1100202012053 is a prime.

It is a super-2 number, since 2×11002020121812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100202012281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550101006090 + 550101006091.

It is an arithmetic number, because the mean of its divisors is an integer number (550101006091).

Almost surely, 21100202012181 is an apocalyptic number.

It is an amenable number.

1100202012181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100202012181 is an equidigital number, since it uses as much as digits as its factorization.

1100202012181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64, while the sum is 19.

Adding to 1100202012181 its reverse (1812102020011), we get a palindrome (2912304032192).

The spelling of 1100202012181 in words is "one trillion, one hundred billion, two hundred two million, twelve thousand, one hundred eighty-one".