1100211133001 has 2 divisors, whose sum is σ = 1100211133002. Its totient is φ = 1100211133000.

The previous prime is 1100211132991. The next prime is 1100211133003. The reversal of 1100211133001 is 1003311120011.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 581200393225 + 519010739776 = 762365^2 + 720424^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100211133001 - 2²² = 1100206938697 is a prime.

It is a super-2 number, since 2×1100211133001² (a number of 25 digits) contains 22 as substring.

Together with 1100211133003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1100211133003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550105566500 + 550105566501.

It is an arithmetic number, because the mean of its divisors is an integer number (550105566501).

Almost surely, 2^{1100211133001} is an apocalyptic number.

It is an amenable number.

1100211133001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100211133001 is an equidigital number, since it uses as much as digits as its factorization.

1100211133001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 1100211133001 its reverse (1003311120011), we get a palindrome (2103522253012).

The spelling of 1100211133001 in words is "one trillion, one hundred billion, two hundred eleven million, one hundred thirty-three thousand, one".