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11002133011997 is a prime number
BaseRepresentation
bin1010000000011010001000…
…1110101101111000011101
31102221210102120021220200202
42200012202032231320131
52420224332022340442
635222150553233245
72213610053402231
oct240064216557035
942853376256622
1011002133011997
113561a84295446
121298354102825
1361a65c2ccb2a
142a07129765c1
151412cda92c32
hexa01a23ade1d

11002133011997 has 2 divisors, whose sum is σ = 11002133011998. Its totient is φ = 11002133011996.

The previous prime is 11002133011993. The next prime is 11002133012053. The reversal of 11002133011997 is 79911033120011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6589868921476 + 4412264090521 = 2567074^2 + 2100539^2 .

It is a cyclic number.

It is not a de Polignac number, because 11002133011997 - 22 = 11002133011993 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11002133011997.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11002133011993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501066505998 + 5501066505999.

It is an arithmetic number, because the mean of its divisors is an integer number (5501066505999).

Almost surely, 211002133011997 is an apocalyptic number.

It is an amenable number.

11002133011997 is a deficient number, since it is larger than the sum of its proper divisors (1).

11002133011997 is an equidigital number, since it uses as much as digits as its factorization.

11002133011997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10206, while the sum is 38.

The spelling of 11002133011997 in words is "eleven trillion, two billion, one hundred thirty-three million, eleven thousand, nine hundred ninety-seven".