Base | Representation |
---|---|
bin | 110011001110111010… |
… | …0101000000111111111 |
3 | 101111222121210202021112 |
4 | 1212131310220013333 |
5 | 3300311113014101 |
6 | 122313213152235 |
7 | 10643306402516 |
oct | 1463564500777 |
9 | 344877722245 |
10 | 110022001151 |
11 | 42729607987 |
12 | 193a618b67b |
13 | a4b4c3113a |
14 | 547a0ad67d |
15 | 2cddee16bb |
hex | 199dd281ff |
110022001151 has 2 divisors, whose sum is σ = 110022001152. Its totient is φ = 110022001150.
The previous prime is 110022001087. The next prime is 110022001153. The reversal of 110022001151 is 151100220011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110022001151 - 26 = 110022001087 is a prime.
Together with 110022001153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110022001153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55011000575 + 55011000576.
It is an arithmetic number, because the mean of its divisors is an integer number (55011000576).
Almost surely, 2110022001151 is an apocalyptic number.
110022001151 is a deficient number, since it is larger than the sum of its proper divisors (1).
110022001151 is an equidigital number, since it uses as much as digits as its factorization.
110022001151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20, while the sum is 14.
Adding to 110022001151 its reverse (151100220011), we get a palindrome (261122221162).
The spelling of 110022001151 in words is "one hundred ten billion, twenty-two million, one thousand, one hundred fifty-one".
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