Base | Representation |
---|---|
bin | 10100011111100100… |
… | …01001010111000111 |
3 | 1001101202121210021120 |
4 | 22033302021113013 |
5 | 140013032101043 |
6 | 5015423445023 |
7 | 536434226022 |
oct | 121762112707 |
9 | 31352553246 |
10 | 11002222023 |
11 | 4736516281 |
12 | 2170756773 |
13 | 1064524b60 |
14 | 7652cc1b9 |
15 | 445d7c983 |
hex | 28fc895c7 |
11002222023 has 64 divisors (see below), whose sum is σ = 16991600640. Its totient is φ = 6275947392.
The previous prime is 11002222013. The next prime is 11002222051. The reversal of 11002222023 is 32022220011.
It is a happy number.
It is not a de Polignac number, because 11002222023 - 212 = 11002217927 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11002221993 and 11002222011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11002222013) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 8290386 + ... + 8291712.
It is an arithmetic number, because the mean of its divisors is an integer number (265493760).
Almost surely, 211002222023 is an apocalyptic number.
11002222023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11002222023 is a deficient number, since it is larger than the sum of its proper divisors (5989378617).
11002222023 is a wasteful number, since it uses less digits than its factorization.
11002222023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1596.
The product of its (nonzero) digits is 96, while the sum is 15.
Adding to 11002222023 its reverse (32022220011), we get a palindrome (43024442034).
The spelling of 11002222023 in words is "eleven billion, two million, two hundred twenty-two thousand, twenty-three".
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