Base | Representation |
---|---|
bin | 10000000000101011011… |
… | …100001100011100000111 |
3 | 10220011220122111100002122 |
4 | 100000223130030130013 |
5 | 121011243023022142 |
6 | 2201235443000155 |
7 | 142326661266011 |
oct | 20005334143407 |
9 | 3804818440078 |
10 | 1100240439047 |
11 | 394678054452 |
12 | 15929836905b |
13 | 7c9a1850bb9 |
14 | 3b3753b51b1 |
15 | 1d946b471d2 |
hex | 1002b70c707 |
1100240439047 has 2 divisors, whose sum is σ = 1100240439048. Its totient is φ = 1100240439046.
The previous prime is 1100240439037. The next prime is 1100240439061. The reversal of 1100240439047 is 7409340420011.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1100240439047 - 226 = 1100173330183 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1100240438998 and 1100240439016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100240439017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550120219523 + 550120219524.
It is an arithmetic number, because the mean of its divisors is an integer number (550120219524).
Almost surely, 21100240439047 is an apocalyptic number.
1100240439047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100240439047 is an equidigital number, since it uses as much as digits as its factorization.
1100240439047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 35.
Adding to 1100240439047 its reverse (7409340420011), we get a palindrome (8509580859058).
The spelling of 1100240439047 in words is "one trillion, one hundred billion, two hundred forty million, four hundred thirty-nine thousand, forty-seven".
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