11002434330413 has 2 divisors, whose sum is σ = 11002434330414. Its totient is φ = 11002434330412.

The previous prime is 11002434330409. The next prime is 11002434330431. The reversal of 11002434330413 is 31403343420011.

It is a happy number.

Together with next prime (11002434330431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8386364230084 + 2616070100329 = 2895922^2 + 1617427^2 .

It is a cyclic number.

It is not a de Polignac number, because 11002434330413 - 2² = 11002434330409 is a prime.

It is a super-2 number, since 2×11002434330413² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11002434330913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501217165206 + 5501217165207.

It is an arithmetic number, because the mean of its divisors is an integer number (5501217165207).

Almost surely, 2^{11002434330413} is an apocalyptic number.

It is an amenable number.

11002434330413 is a deficient number, since it is larger than the sum of its proper divisors (1).

11002434330413 is an equidigital number, since it uses as much as digits as its factorization.

11002434330413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 11002434330413 its reverse (31403343420011), we get a palindrome (42405777750424).

The spelling of 11002434330413 in words is "eleven trillion, two billion, four hundred thirty-four million, three hundred thirty thousand, four hundred thirteen".