Base | Representation |
---|---|
bin | 10000000000101111000… |
… | …001011110100110011100 |
3 | 10220012001211121000011021 |
4 | 100000233001132212130 |
5 | 121011403414410122 |
6 | 2201245431133524 |
7 | 142331321212216 |
oct | 20005701364634 |
9 | 3805054530137 |
10 | 1100300544412 |
11 | 3946a8a77503 |
12 | 1592b45142a4 |
13 | 7c9b1136ac4 |
14 | 3b37d37d5b6 |
15 | 1d94c06b1c7 |
hex | 1002f05e99c |
1100300544412 has 12 divisors (see below), whose sum is σ = 2038792185360. Its totient is φ = 517788491456.
The previous prime is 1100300544391. The next prime is 1100300544433. The reversal of 1100300544412 is 2144450030011.
It is an interprime number because it is at equal distance from previous prime (1100300544391) and next prime (1100300544433).
It is a super-2 number, since 2×11003005444122 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8090445112 + ... + 8090445247.
It is an arithmetic number, because the mean of its divisors is an integer number (169899348780).
Almost surely, 21100300544412 is an apocalyptic number.
It is an amenable number.
1100300544412 is a deficient number, since it is larger than the sum of its proper divisors (938491640948).
1100300544412 is a wasteful number, since it uses less digits than its factorization.
1100300544412 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16180890380 (or 16180890378 counting only the distinct ones).
The product of its (nonzero) digits is 1920, while the sum is 25.
Adding to 1100300544412 its reverse (2144450030011), we get a palindrome (3244750574423).
The spelling of 1100300544412 in words is "one trillion, one hundred billion, three hundred million, five hundred forty-four thousand, four hundred twelve".
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