110030601011143 has 2 divisors, whose sum is σ = 110030601011144. Its totient is φ = 110030601011142.

The previous prime is 110030601011119. The next prime is 110030601011197. The reversal of 110030601011143 is 341110106030011.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110030601011143 is a prime.

It is a super-3 number, since 3×110030601011143³ (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110030601017143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55015300505571 + 55015300505572.

It is an arithmetic number, because the mean of its divisors is an integer number (55015300505572).

Almost surely, 2^{110030601011143} is an apocalyptic number.

110030601011143 is a deficient number, since it is larger than the sum of its proper divisors (1).

110030601011143 is an equidigital number, since it uses as much as digits as its factorization.

110030601011143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 110030601011143 its reverse (341110106030011), we get a palindrome (451140707041154).

The spelling of 110030601011143 in words is "one hundred ten trillion, thirty billion, six hundred one million, eleven thousand, one hundred forty-three".