110030601011119 has 2 divisors, whose sum is σ = 110030601011120. Its totient is φ = 110030601011118.

The previous prime is 110030601011087. The next prime is 110030601011143. The reversal of 110030601011119 is 911110106030011.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 110030601011119 - 2⁵ = 110030601011087 is a prime.

It is a super-3 number, since 3×110030601011119³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 110030601011093 and 110030601011102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110030601311119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55015300505559 + 55015300505560.

It is an arithmetic number, because the mean of its divisors is an integer number (55015300505560).

Almost surely, 2^{110030601011119} is an apocalyptic number.

110030601011119 is a deficient number, since it is larger than the sum of its proper divisors (1).

110030601011119 is an equidigital number, since it uses as much as digits as its factorization.

110030601011119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 25.

The spelling of 110030601011119 in words is "one hundred ten trillion, thirty billion, six hundred one million, eleven thousand, one hundred nineteen".