Base | Representation |
---|---|
bin | 11001000001001010011101… |
… | …011110001000110000010110 |
3 | 112102120212112112020102212102 |
4 | 121001022131132020300112 |
5 | 103410222210203041042 |
6 | 1030003332423122102 |
7 | 32114325403225445 |
oct | 3101123536106026 |
9 | 472525475212772 |
10 | 110031114112022 |
11 | 32071a2a458064 |
12 | 104109255a3332 |
13 | 4951b7441862c |
14 | 1d2576a31cd5c |
15 | cac26605db32 |
hex | 64129d788c16 |
110031114112022 has 8 divisors (see below), whose sum is σ = 165048201075456. Its totient is φ = 55015047086872.
The previous prime is 110031114112021. The next prime is 110031114112063. The reversal of 110031114112022 is 220211411130011.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 110031114111985 and 110031114112003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110031114112021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 254714813 + ... + 255146424.
It is an arithmetic number, because the mean of its divisors is an integer number (20631025134432).
Almost surely, 2110031114112022 is an apocalyptic number.
110031114112022 is a deficient number, since it is larger than the sum of its proper divisors (55017086963434).
110031114112022 is a wasteful number, since it uses less digits than its factorization.
110031114112022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 509969142.
The product of its (nonzero) digits is 96, while the sum is 20.
Adding to 110031114112022 its reverse (220211411130011), we get a palindrome (330242525242033).
The spelling of 110031114112022 in words is "one hundred ten trillion, thirty-one billion, one hundred fourteen million, one hundred twelve thousand, twenty-two".
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