Base | Representation |
---|---|
bin | 10000000000101111101… |
… | …110010110000111011111 |
3 | 10220012002122201120012221 |
4 | 100000233232112013133 |
5 | 121011414422244033 |
6 | 2201250531210211 |
7 | 142331523200041 |
oct | 20005756260737 |
9 | 3805078646187 |
10 | 1100312306143 |
11 | 394704680246 |
12 | 1592b8446967 |
13 | 7c9b36c44cb |
14 | 3b380b61a91 |
15 | 1d94d0e112d |
hex | 1002fb961df |
1100312306143 has 2 divisors, whose sum is σ = 1100312306144. Its totient is φ = 1100312306142.
The previous prime is 1100312306131. The next prime is 1100312306173. The reversal of 1100312306143 is 3416032130011.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1100312306143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100312306113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550156153071 + 550156153072.
It is an arithmetic number, because the mean of its divisors is an integer number (550156153072).
Almost surely, 21100312306143 is an apocalyptic number.
1100312306143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100312306143 is an equidigital number, since it uses as much as digits as its factorization.
1100312306143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1100312306143 its reverse (3416032130011), we get a palindrome (4516344436154).
The spelling of 1100312306143 in words is "one trillion, one hundred billion, three hundred twelve million, three hundred six thousand, one hundred forty-three".
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