11003313103 has 2 divisors, whose sum is σ = 11003313104. Its totient is φ = 11003313102.

The previous prime is 11003313089. The next prime is 11003313119. The reversal of 11003313103 is 30131330011.

It is an a-pointer prime, because the next prime (11003313119) can be obtained adding 11003313103 to its sum of digits (16).

It is a weak prime.

It is an emirp because it is prime and its reverse (30131330011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11003313103 - 2⁹ = 11003312591 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11003313173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501656551 + 5501656552.

It is an arithmetic number, because the mean of its divisors is an integer number (5501656552).

Almost surely, 2^11003313103 is an apocalyptic number.

11003313103 is a deficient number, since it is larger than the sum of its proper divisors (1).

11003313103 is an equidigital number, since it uses as much as digits as its factorization.

11003313103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 11003313103 its reverse (30131330011), we get a palindrome (41134643114).

The spelling of 11003313103 in words is "eleven billion, three million, three hundred thirteen thousand, one hundred three".