11003320434101 has 2 divisors, whose sum is σ = 11003320434102. Its totient is φ = 11003320434100.

The previous prime is 11003320434097. The next prime is 11003320434103. The reversal of 11003320434101 is 10143402330011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9450121551025 + 1553198883076 = 3074105^2 + 1246274^2 .

It is a cyclic number.

It is not a de Polignac number, because 11003320434101 - 2² = 11003320434097 is a prime.

It is a super-3 number, since 3×11003320434101³ (a number of 40 digits) contains 333 as substring.

Together with 11003320434103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11003320434103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501660217050 + 5501660217051.

It is an arithmetic number, because the mean of its divisors is an integer number (5501660217051).

Almost surely, 2^{11003320434101} is an apocalyptic number.

It is an amenable number.

11003320434101 is a deficient number, since it is larger than the sum of its proper divisors (1).

11003320434101 is an equidigital number, since it uses as much as digits as its factorization.

11003320434101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 11003320434101 its reverse (10143402330011), we get a palindrome (21146722764112).

The spelling of 11003320434101 in words is "eleven trillion, three billion, three hundred twenty million, four hundred thirty-four thousand, one hundred one".