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1100333121413 is a prime number
BaseRepresentation
bin10000000000110000111…
…101101111111110000101
310220012011002220002101212
4100000300331233332011
5121011440234341123
62201252553301205
7142332165133001
oct20006075577605
93805132802355
101100333121413
113947153a8049
12159303404805
137c9b7b01a36
143b38381d701
151d94ed53878
hex10030f6ff85

1100333121413 has 2 divisors, whose sum is σ = 1100333121414. Its totient is φ = 1100333121412.

The previous prime is 1100333121337. The next prime is 1100333121421. The reversal of 1100333121413 is 3141213330011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1096162932484 + 4170188929 = 1046978^2 + 64577^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100333121413 - 28 = 1100333121157 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100333121493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550166560706 + 550166560707.

It is an arithmetic number, because the mean of its divisors is an integer number (550166560707).

Almost surely, 21100333121413 is an apocalyptic number.

It is an amenable number.

1100333121413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100333121413 is an equidigital number, since it uses as much as digits as its factorization.

1100333121413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 1100333121413 its reverse (3141213330011), we get a palindrome (4241546451424).

The spelling of 1100333121413 in words is "one trillion, one hundred billion, three hundred thirty-three million, one hundred twenty-one thousand, four hundred thirteen".