Base | Representation |
---|---|
bin | 10000000000110000111… |
… | …101101111111110000101 |
3 | 10220012011002220002101212 |
4 | 100000300331233332011 |
5 | 121011440234341123 |
6 | 2201252553301205 |
7 | 142332165133001 |
oct | 20006075577605 |
9 | 3805132802355 |
10 | 1100333121413 |
11 | 3947153a8049 |
12 | 159303404805 |
13 | 7c9b7b01a36 |
14 | 3b38381d701 |
15 | 1d94ed53878 |
hex | 10030f6ff85 |
1100333121413 has 2 divisors, whose sum is σ = 1100333121414. Its totient is φ = 1100333121412.
The previous prime is 1100333121337. The next prime is 1100333121421. The reversal of 1100333121413 is 3141213330011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1096162932484 + 4170188929 = 1046978^2 + 64577^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100333121413 - 28 = 1100333121157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100333121493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550166560706 + 550166560707.
It is an arithmetic number, because the mean of its divisors is an integer number (550166560707).
Almost surely, 21100333121413 is an apocalyptic number.
It is an amenable number.
1100333121413 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100333121413 is an equidigital number, since it uses as much as digits as its factorization.
1100333121413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1100333121413 its reverse (3141213330011), we get a palindrome (4241546451424).
The spelling of 1100333121413 in words is "one trillion, one hundred billion, three hundred thirty-three million, one hundred twenty-one thousand, four hundred thirteen".
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