1100333121421 has 2 divisors, whose sum is σ = 1100333121422. Its totient is φ = 1100333121420.

The previous prime is 1100333121413. The next prime is 1100333121467. The reversal of 1100333121421 is 1241213330011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1075080733321 + 25252388100 = 1036861^2 + 158910^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100333121421 - 2³ = 1100333121413 is a prime.

It is a super-2 number, since 2×1100333121421² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100333121392 and 1100333121401.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100333121721) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550166560710 + 550166560711.

It is an arithmetic number, because the mean of its divisors is an integer number (550166560711).

Almost surely, 2^{1100333121421} is an apocalyptic number.

It is an amenable number.

1100333121421 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100333121421 is an equidigital number, since it uses as much as digits as its factorization.

1100333121421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1100333121421 its reverse (1241213330011), we get a palindrome (2341546451432).

The spelling of 1100333121421 in words is "one trillion, one hundred billion, three hundred thirty-three million, one hundred twenty-one thousand, four hundred twenty-one".