Base | Representation |
---|---|
bin | 11001000001001101001001… |
… | …100110101101101010101111 |
3 | 112102121010222210101110101011 |
4 | 121001031021212231222233 |
5 | 103410244114010312034 |
6 | 1030004531145330051 |
7 | 32114460101224123 |
oct | 3101151146555257 |
9 | 472533883343334 |
10 | 110034002041519 |
11 | 32073181632256 |
12 | 104113b0796927 |
13 | 495221482125a |
14 | 1d25961ab1583 |
15 | cac384866864 |
hex | 6413499adaaf |
110034002041519 has 2 divisors, whose sum is σ = 110034002041520. Its totient is φ = 110034002041518.
The previous prime is 110034002041493. The next prime is 110034002041541. The reversal of 110034002041519 is 915140200430011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110034002041519 - 25 = 110034002041487 is a prime.
It is a super-2 number, since 2×1100340020415192 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110034002042519) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55017001020759 + 55017001020760.
It is an arithmetic number, because the mean of its divisors is an integer number (55017001020760).
Almost surely, 2110034002041519 is an apocalyptic number.
110034002041519 is a deficient number, since it is larger than the sum of its proper divisors (1).
110034002041519 is an equidigital number, since it uses as much as digits as its factorization.
110034002041519 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 31.
The spelling of 110034002041519 in words is "one hundred ten trillion, thirty-four billion, two million, forty-one thousand, five hundred nineteen".
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