Base | Representation |
---|---|
bin | 11001000001001101001001… |
… | …100110101101101010010101 |
3 | 112102121010222210101110100012 |
4 | 121001031021212231222111 |
5 | 103410244114010311433 |
6 | 1030004531145330005 |
7 | 32114460101224055 |
oct | 3101151146555225 |
9 | 472533883343305 |
10 | 110034002041493 |
11 | 32073181632232 |
12 | 104113b0796905 |
13 | 495221482123a |
14 | 1d25961ab1565 |
15 | cac384866848 |
hex | 6413499ada95 |
110034002041493 has 2 divisors, whose sum is σ = 110034002041494. Its totient is φ = 110034002041492.
The previous prime is 110034002041489. The next prime is 110034002041519. The reversal of 110034002041493 is 394140200430011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 59135223343249 + 50898778698244 = 7689943^2 + 7134338^2 .
It is a cyclic number.
It is not a de Polignac number, because 110034002041493 - 22 = 110034002041489 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110034002041433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55017001020746 + 55017001020747.
It is an arithmetic number, because the mean of its divisors is an integer number (55017001020747).
Almost surely, 2110034002041493 is an apocalyptic number.
It is an amenable number.
110034002041493 is a deficient number, since it is larger than the sum of its proper divisors (1).
110034002041493 is an equidigital number, since it uses as much as digits as its factorization.
110034002041493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 32.
The spelling of 110034002041493 in words is "one hundred ten trillion, thirty-four billion, two million, forty-one thousand, four hundred ninety-three".
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