Base | Representation |
---|---|
bin | 1010000000100001100110… |
… | …0101110011111111111111 |
3 | 1102221222121010102122100202 |
4 | 2200020121211303333333 |
5 | 2420242432200230241 |
6 | 35223121410514115 |
7 | 2214010510625231 |
oct | 240103145637777 |
9 | 42858533378322 |
10 | 11004135555071 |
11 | 356291170971a |
12 | 129881289593b |
13 | 61a8bb157869 |
14 | 2a08628d4251 |
15 | 1413997a8d9b |
hex | a0219973fff |
11004135555071 has 2 divisors, whose sum is σ = 11004135555072. Its totient is φ = 11004135555070.
The previous prime is 11004135555053. The next prime is 11004135555097. The reversal of 11004135555071 is 17055553140011.
It is a weak prime.
It is an emirp because it is prime and its reverse (17055553140011) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11004135555071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11004135755071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502067777535 + 5502067777536.
It is an arithmetic number, because the mean of its divisors is an integer number (5502067777536).
Almost surely, 211004135555071 is an apocalyptic number.
11004135555071 is a deficient number, since it is larger than the sum of its proper divisors (1).
11004135555071 is an equidigital number, since it uses as much as digits as its factorization.
11004135555071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 52500, while the sum is 38.
Adding to 11004135555071 its reverse (17055553140011), we get a palindrome (28059688695082).
The spelling of 11004135555071 in words is "eleven trillion, four billion, one hundred thirty-five million, five hundred fifty-five thousand, seventy-one".
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