Base | Representation |
---|---|
bin | 10100011111110011… |
… | …01111011111111111 |
3 | 1001101220100221201121 |
4 | 22033321233133333 |
5 | 140014034310442 |
6 | 5015534251411 |
7 | 536460161236 |
oct | 121771573777 |
9 | 31356327647 |
10 | 11004213247 |
11 | 4737656315 |
12 | 2171356b67 |
13 | 1064a712b1 |
14 | 765689b1d |
15 | 446122967 |
hex | 28fe6f7ff |
11004213247 has 2 divisors, whose sum is σ = 11004213248. Its totient is φ = 11004213246.
The previous prime is 11004213221. The next prime is 11004213277. The reversal of 11004213247 is 74231240011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11004213247 - 215 = 11004180479 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11004213277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502106623 + 5502106624.
It is an arithmetic number, because the mean of its divisors is an integer number (5502106624).
Almost surely, 211004213247 is an apocalyptic number.
11004213247 is a deficient number, since it is larger than the sum of its proper divisors (1).
11004213247 is an equidigital number, since it uses as much as digits as its factorization.
11004213247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 11004213247 its reverse (74231240011), we get a palindrome (85235453258).
The spelling of 11004213247 in words is "eleven billion, four million, two hundred thirteen thousand, two hundred forty-seven".
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