Base | Representation |
---|---|
bin | 10100011111111010… |
… | …00100101001101101 |
3 | 1001101222000022100112 |
4 | 22033331010221231 |
5 | 140014300230232 |
6 | 5020005105405 |
7 | 536500455521 |
oct | 121775045155 |
9 | 31358008315 |
10 | 11005086317 |
11 | 47380a2265 |
12 | 21716b8265 |
13 | 1064cb87c4 |
14 | 765835d81 |
15 | 4462464b2 |
hex | 28ff44a6d |
11005086317 has 2 divisors, whose sum is σ = 11005086318. Its totient is φ = 11005086316.
The previous prime is 11005086269. The next prime is 11005086341. The reversal of 11005086317 is 71368050011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9397557481 + 1607528836 = 96941^2 + 40094^2 .
It is a cyclic number.
It is not a de Polignac number, because 11005086317 - 210 = 11005085293 is a prime.
It is a super-2 number, since 2×110050863172 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11005086347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502543158 + 5502543159.
It is an arithmetic number, because the mean of its divisors is an integer number (5502543159).
Almost surely, 211005086317 is an apocalyptic number.
It is an amenable number.
11005086317 is a deficient number, since it is larger than the sum of its proper divisors (1).
11005086317 is an equidigital number, since it uses as much as digits as its factorization.
11005086317 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5040, while the sum is 32.
The spelling of 11005086317 in words is "eleven billion, five million, eighty-six thousand, three hundred seventeen".
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