110056131403 has 2 divisors, whose sum is σ = 110056131404. Its totient is φ = 110056131402.

The previous prime is 110056131401. The next prime is 110056131457. The reversal of 110056131403 is 304131650011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 110056131403 - 2¹ = 110056131401 is a prime.

It is a super-2 number, since 2×110056131403² (a number of 23 digits) contains 22 as substring.

Together with 110056131401, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (110056131401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55028065701 + 55028065702.

It is an arithmetic number, because the mean of its divisors is an integer number (55028065702).

Almost surely, 2^110056131403 is an apocalyptic number.

110056131403 is a deficient number, since it is larger than the sum of its proper divisors (1).

110056131403 is an equidigital number, since it uses as much as digits as its factorization.

110056131403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 110056131403 its reverse (304131650011), we get a palindrome (414187781414).

The spelling of 110056131403 in words is "one hundred ten billion, fifty-six million, one hundred thirty-one thousand, four hundred three".