11005769417053 has 2 divisors, whose sum is σ = 11005769417054. Its totient is φ = 11005769417052.

The previous prime is 11005769416997. The next prime is 11005769417077. The reversal of 11005769417053 is 35071496750011.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9171703224324 + 1834066192729 = 3028482^2 + 1354277^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11005769417053 is a prime.

It is a super-2 number, since 2×11005769417053² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11005769416988 and 11005769417006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11005769414053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502884708526 + 5502884708527.

It is an arithmetic number, because the mean of its divisors is an integer number (5502884708527).

Almost surely, 2^{11005769417053} is an apocalyptic number.

It is an amenable number.

11005769417053 is a deficient number, since it is larger than the sum of its proper divisors (1).

11005769417053 is an equidigital number, since it uses as much as digits as its factorization.

11005769417053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 793800, while the sum is 49.

The spelling of 11005769417053 in words is "eleven trillion, five billion, seven hundred sixty-nine million, four hundred seventeen thousand, fifty-three".