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11006453301231 = 34721660850053
BaseRepresentation
bin1010000000101010001110…
…1111010011111111101111
31102222012120122200100101010
42200022203233103333233
52420312204021114411
635224143404120303
72214122113300533
oct240124357237757
942865518610333
1011006453301231
1135638a0a50713
12129915ab36093
1361ab9a3a42ab
142a0a02661bc3
15141482ed37a6
hexa02a3bd3fef

11006453301231 has 12 divisors (see below), whose sum is σ = 14994154287512. Its totient is φ = 7181515624848.

The previous prime is 11006453301199. The next prime is 11006453301247. The reversal of 11006453301231 is 13210335460011.

It is not a de Polignac number, because 11006453301231 - 25 = 11006453301199 is a prime.

It is a super-2 number, since 2×110064533012312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11006453301331) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 830418400 + ... + 830431653.

Almost surely, 211006453301231 is an apocalyptic number.

11006453301231 is a deficient number, since it is larger than the sum of its proper divisors (3987700986281).

11006453301231 is an equidigital number, since it uses as much as digits as its factorization.

11006453301231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1660850150 (or 1660850103 counting only the distinct ones).

The product of its (nonzero) digits is 6480, while the sum is 30.

Adding to 11006453301231 its reverse (13210335460011), we get a palindrome (24216788761242).

The spelling of 11006453301231 in words is "eleven trillion, six billion, four hundred fifty-three million, three hundred one thousand, two hundred thirty-one".

Divisors: 1 3 47 141 2209 6627 1660850053 4982550159 78059952491 234179857473 3668817767077 11006453301231